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-48x=-7x^2=64
We move all terms to the left:
-48x-(-7x^2)=0
We get rid of parentheses
7x^2-48x=0
a = 7; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·7·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*7}=\frac{0}{14} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*7}=\frac{96}{14} =6+6/7 $
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